3x^2+x-784=0

Solution for 3x^2+x-784=0 equation:

3x^2+x-784=0

a = 3; b = 1; c = -784;
Δ = b2-4ac
Δ = 12-4·3·(-784)
Δ = 9409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9409}=97$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-97}{2*3}=\frac{-98}{6}
=-16+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+97}{2*3}=\frac{96}{6}
=16
$